Întrebare ajutor rezolvare

\[\dfrac{1}{2}:2\dfrac{1}{4}+\dfrac{1}{\dfrac{3}{5}\cdot2\dfrac{1}{3}+3\dfrac{4}{5}}\cdot\dfrac{5\cdot}{13}\cdot3\dfrac{2}{3}\]=
\[\dfrac{1}{2}:\dfrac{9}{4}+\dfrac{1}{\dfrac{3}{5}\cdot\dfrac{7}{3}+\dfrac{19}{5}}\dfrac{5}{13}\cdot\dfrac{11}{3}\]=
\[\dfrac{4}{18}+\dfrac{1}{\dfrac{21}{15}+\dfrac{57}{15}}\cdot\dfrac{55}{39}\]=
\[=\dfrac{4}{18}+\dfrac{15}{78}\cdot\dfrac{55}{39}\]
=\[=\dfrac{676}{3042}+\dfrac{825}{3042}\]
\[=\dfrac{1501}{3042}\]

1/2 : 2 intregi1/4 + 1
totul supra
( 3/5 X 2intregi 1/3+3intregi4/5) X 5/13x3 intregi2/3

Atunci exercitiul arata cam asa:
\[\dfrac{\dfrac{1}{2}:2\dfrac{1}{4}+1}{(\dfrac{3}{5}\cdot2\dfrac{1}{3}+3\dfrac{4}{5})\cdot\dfrac{5}{13}\cdot3\dfrac{2}{3}}\]
daca este asa rog sa confirmati .

da asa arata exercitiul

atunci rezolvarea este asa:
\[\dfrac{\dfrac{1}{2}\cdot\dfrac{4}{9}+1}{(\dfrac{3}{5}\cdot\dfrac{7}{3}+\dfrac{19}{5})\cdot\dfrac{5}{13}\cdot\dfrac{11}{3}=}\]=
\[\dfrac{\dfrac{4}{18}+1}{(\dfrac{7}{5}+\dfrac{19}{5})\cdot\dfrac{5}{13}\cdot\dfrac{11}{3}}\]=
\[\dfrac{\dfrac{4}{18}+1}{\dfrac{26}{5}\cdot\dfrac{5}{13}\cdot\dfrac{11}{3}}\]=\[\dfrac{\dfrac{22}{18}}{\dfrac{22}{3}}\]=
\[\dfrac{22}{18}\cdot\dfrac{3}{22}\]=\[\dfrac{1}{6}\]

sa se afle punctul M'simetric punctului M in raport cu dreapta sau in raport cu planul M(-1,0,-1),2x+6y-2z+11=0